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Anyway I watched Spiderman 2 yesterday and I can’t stop thinking about that scene. The one where he stops a whole subway car by himself?? It just doesn't seem possible. Even in a superhero movie where you are suspending disbelief. Maybe I can't let people enjoy things.
According to Wikipedia, the average NYC subway car is ~84,000 lbs, which is ~38,000 kg. Assuming there are 10 subway cars, that means 380,000 kg. In the scene, you get a brief glimpse of the speedometer, which reads 80 mph, which is 35.8 m/s.
Therefore:
Momentum (p = mv)
p=380,000 kg×35.8 m/sp = 380,000 \, \text{kg} \times 35.8 \, \text{m/s} p=13,604,000 kg⋅m/sp = 13,604,000 \, \text{kg} \cdot \text{m/s}
That’s over 13 million kg·m/s of momentum. In the scene, He takes about 20 seconds to stop the train, so the average force is found using:
F=ΔpΔtF = \frac{\Delta p}{\Delta t} F=13,604,000 kg⋅m/s20 s=680,200 NF = \frac{13,604,000 \, \text{kg} \cdot \text{m/s}}{20 \, \text{s}} = 680,200 \, \text{N}
So, that's 69,000 kg on his webs. If we assume 10 web strands, each with 2 cm diameter, we can calculate the amount of stress on each web. The cross-sectional area per web is:
Asingle=π×(0.01 m)2=3.14×10−4 m2A_{\text{single}} = \pi \times (0.01 \, \text{m})^2 = 3.14 \times 10^{-4} \, \text{m}^2 Atotal=10×3.14×10−4 m2=0.00314 m2A_{\text{total}} = 10 \times 3.14 \times 10^{-4} \, \text{m}^2 = 0.00314 \, \text{m}^2
Stress (Force ÷ Area)
Stress=680,200 N0.00314 m2=216,560,509 Pa=216.6 MPa\text{Stress} = \frac{680,200 \, \text{N}}{0.00314 \, \text{m}^2} = 216,560,509 \, \text{Pa} = 216.6 \, \text{MPa}
According to InChemistry Magazinereal spider silk has a Tensile Strength of 0.45 GPa to 2.0 Gpa (450 MPa to 2000 MPa).
Which means that even the weakest spider silk is twice as strong as what spiderman would need to stop that train! So very surprisingly accurate. However, Spiderman himself should not be fine. He would be holding 680,200 Newtons for 20 seconds, which would liquify every joint in his body.
According to International Journal of Occupational Safety and Ergonomics The greatest pull strength of a man was recorded to be 400 Newtons. So not even close.
Assuming it takes him 5 blocks (400m) to stop the train, this also means that the work done on the train can be calculated as:
W=F⋅dW = F \cdot d W=680,200 N×400 mW = 680,200 \, \text{N} \times 400 \, \text{m} W=272,080,000 JW = 272,080,000 \, \text{J}
So the work done by Spiderman is 272 MJ (MegaJoules)\mathbf{272 \, \text{MJ}} \ (\text{MegaJoules})
Which is equal to 64,966.083883 Calories, which is approx. 43 gallons of my beloved miso soup. Except he can't enjoy any of it. Because he would be DEAD!! LIQUIFIED!!! GONE!!
memdle is a
memdle is a memory game